Respuesta :
This is an incomplete question, here is a complete question.
Consider the following equilibrium at 100°C.
[tex]COBr_2(g)\rightleftharpoons CO(g)+Br_2(g)[/tex]
[tex]K_c=4.74\times 10^4[/tex]
Concentration at equilibrium:
[tex][COBr_2]=1.58\times 10^{-6}M[/tex]
[tex][Co]=2.78\times 10^{-3}M[/tex]
[tex][Br_2]=2.51\times 10^{-5}M[/tex]
If a system has a reaction quotient of 2.13 × 10⁻¹⁵ at 100°c, what will happen to the concentrations of COBr₂, Co and Br₂ as the reaction proceeds to equilibrium?
Answer : The concentrations of Co and Br₂ decreases and the concentrations of COBr₂ increases.
Explanation :
Reaction quotient (Q) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.
The given balanced chemical reaction is,
[tex]COBr_2(g)\rightleftharpoons CO(g)+Br_2(g)[/tex]
The expression for reaction quotient will be :
[tex]Q=\frac{[CO][Br_2]}{[COBr_2]}[/tex]
In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.
Now put all the given values in this expression, we get
[tex]Q=\frac{(2.78\times 10^{-3})\times (2.51\times 10^{-5})}{(1.58\times 10^{-6})}=4.42\times 10^{-2}[/tex]
The given equilibrium constant value is, [tex]K_c=4.74\times 10^4[/tex]
Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.
There are 3 conditions:
When [tex]Q>K_c[/tex] that means product > reactant. So, the reaction is reactant favored.
When [tex]Q<K_c[/tex] that means reactant > product. So, the reaction is product favored.
When [tex]Q=K_c[/tex] that means product = reactant. So, the reaction is in equilibrium.
From the above we conclude that, the [tex]Q<K_c[/tex] that means product < reactant. So, the reaction is product favored that means reaction must shift to the product (right) to be in equilibrium.
Hence, the concentrations of Co and Br₂ decreases and the concentrations of COBr₂ increases.