Question

Lacey has $20.02 for a cab ride. There is an initial fee of $5.35 with a $0.46 charge for every mile traveled. This situation is modeled by the equation 0.46m + 5.35 = 20.02, where m represents the number of miles traveled. How many miles can Lacey travel? (round to the nearest tenth of a miles traveled)

Answer 1

Answer:

Lacey can travel 31.89 miles.

Step-by-step explanation:

Given:

Lacey has $20.02 for a cab ride. There is an initial fee of $5.35 with a $0.46 charge for every mile traveled.

This situation is modeled by the equation 0.46m + 5.35 = 20.02, where m represents the number of miles traveled.

Now, to find the miles Lacey can travel.

Price Lacey has for cab ride = $20.02.

The initial fee = $5.35.

Charge for per mile traveled = $0.46.

The number of miles traveled represented as $m.$

So, the equation which is modeled according to situation is:

$0.46m + 5.35 = 20.02$

Now, to solve the equation to get the miles Lacey can travel:

$0.46m + 5.35 = 20.02$

Subtracting both sides by 5.35 we get:

$0.46m=14.67$

Dividing both sides by 0.46 we get:

$m=31.89\ miles.$

Therefore, Lacey can travel 31.89 miles.