Answer:
[tex]\frac{3x+10}{x+4}[/tex]
Step-by-step explanation:
Since the two term's denominator's are equal, we multiply each numerator by how many times the denominator goes into the denominator LCM:
[tex]=\frac{(x-1)-(4x-11)}{x+4}[/tex]
#We open the numerator bracket.
*A -ve sign before the bracket changes every sign in the bracket to its opposite, hence:
[tex]=\frac{x-1-4x+11}{x+4}\\\\=\frac{x-4x-1+11}{x+4}\\\\=\frac{3x+10}{x+4}[/tex]
The terms can not be simplified any further and thus the final solution is
[tex]\frac{3x+10}{x+4}[/tex]
#We can not solve for x since the expression is not equated to any variable.