Respuesta :

Answer:

[tex]\frac{3x+10}{x+4}[/tex]

Step-by-step explanation:

Since the two term's denominator's are equal, we multiply each numerator by how many times the denominator goes into the denominator LCM:

[tex]=\frac{(x-1)-(4x-11)}{x+4}[/tex]

#We open the numerator bracket.

*A -ve sign before the bracket changes every sign  in the bracket to its opposite, hence:

[tex]=\frac{x-1-4x+11}{x+4}\\\\=\frac{x-4x-1+11}{x+4}\\\\=\frac{3x+10}{x+4}[/tex]

The terms can not be simplified any further and thus the final solution is

[tex]\frac{3x+10}{x+4}[/tex]

#We can not solve for x since the expression is not equated to any variable.