Respuesta :

1.0461394837700177e-24 moles

The answer fr the following problem is mentioned below.

  • Therefore no of molecules present are 3.79449 × 10^23 molecules

Explanation:

Given:

no of moles (n) = 0.63 moles

We know;

no.of molecules at STP condition ([tex]N_{A}[/tex])= 6.023 ×10^23

To solve:

no of molecules(N)

We know;

to calculate no of molecules present,the formula is mentioned below as follows:

From the ideal gas equation,

n = N ÷ [tex]N_{A}[/tex]

where,

n = no of moles

N = no of molecules

[tex]N_{A}[/tex] = no of molecules at STP conditions(Avogadro number)= 6.023 ×10^23 molecules

0.63 = N ÷ 6.023 ×10^23

N = 0.63 × 6.023 × 10^23

N = 3.79449 × 10^23 molecules

Therefore no of molecules present are 3.79449 × 10^23 molecules