Question

A sample of N2 is placed into a 50ml flask for analysis. At 27°C, the samples pressure is 80 kPa. If the sample is cooled until exerts a pressure of 53 kPa, what is the temperature of the gas?

Answer 1

Answer:

198.8K

Explanation:

Given parameters:

Constant volume  = constant mole  = 50mL

T₁   = 27°C, which gives 27 + 273  = 300K

P₁  = 80kPa

P₂  = 53kPa

T₂  =?

Solution:

Devolving the combined gas law and assuming constant volume, we can solve this problem. The expression obtained will give us a relationship between pressure and temperature.

At constant volume, the pressure of a given mass of gas varies directly with the absolute temperature;

      mathematically;

                   $\frac{P_{1} }{T_{1} } = \frac{P_{2} }{T_{2} }$

   input the parameters and solve for  T₂;

             $\frac{80}{300}$   = $\frac{53}{T_{2} }$

          T₂  = 198.8K