Question

A ball weighing 10 kg traveling at 1.4 m/s hits and rebounds back off a wall and now travels 1.4 m/s in the opposite direction. What is the work done on it?

Answer 1

Answer:

0 J

Explanation:

1/2 (10) (-1.4)^2 = 10J

Answer 2

We have that since

K.E=K.E'

Mb=M_f

The Net work don is Zero

From the question we are told

• A ball weighing 10 kg
• traveling at 1.4 m/s hits and rebounds back off a wall
• and now travels 1.4 m/s in the opposite direction

Generally the equation for the Momentum   is mathematically given as

M=mv

Therefore for going forward

$M_f=10*1.4\\\\M_f=14kgm/s$

Therefore for going backwards

$M_b=10*1.4\\\\M_b=-14kgm/s$

And the equation for the Momentum   is mathematically given as

$K.E=1/2mv^2$

Therefore for going forward

$K.E=1/2(10)(1.4)^2\\\\K.E=9.8J$

Therefore for going backwards

$K.E'=1/2(10)(1.4)^2\\\\K.E'=9.8J$

Therefore

Since

K.E=K.E'

Mb=M_f

The Net work don is Zero

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