Question

Ruth began filing an empty water tank at a constant rate of 3 hours the tank has 147 times pi, m^3 liters of water. Approximately what percent of the tank would be full of water after 9 hours.

Answer 1

Answer:

5.8%

Step-by-step explanation:

Proportions

If we know the constant rate at which a quantity is changing over time, we can set an equation to model the current quantity as a function of time.

We know Ruth began filling an empty water tank at a constant rate of 3 $m^3$ per hour (assuming that unit, not specified in the question).

The tank has a capacity of $147\pi\ m^3$ of water, thus at 9 hours, it has been filled with $3\cdot 9 = 27 \ m^3$ of water.

To compute the percentage of filling, we compare this volume with the total capacity of the tank

$\displaystyle percent=\frac{27}{147\pi}\cdot 100\%=\frac{27}{461.8}\cdot 100\%$

$percent=5.8\%$