Answer:
[tex]e=\frac{1}{4} fg[/tex]
Step-by-step explanation:
Joint variation problem solve using the equation y = kxz.
e ∝ fg
e=kfg
now substitute the values
[tex]4=k*2*8\\4=16k\\k=\frac{4}{16} \\k=\frac{1}{4}[/tex]
The relationship will be:
[tex]e=kfg\\e=\frac{1}{4} fg[/tex]
Answer:
K = 1/4
Step-by-step explanation:
Formula for joint variation is X = Kyz
Where k is the constant and x,z are any given variables.
The question here says that
When e = 4, f = 2, and g = 8If e varies jointly with f and g, what is the constant of variation?
It means that e= k×f×g
And e = 4, f= 2 and g= 8
4 = k × 2 × 8
4 = 16 × k (Now divide through by 16 to get k)
K = 1/4