Answer:
a) 3.43 m/s
Explanation:
Due to the law of conservation of momentum, the total momentum of the bullet - rifle system must be conserved.
The total momentum before the bullet is shot is zero, because they are both at rest, so:
[tex]p_i = 0[/tex]
Instead the total momentum of the system after the shot is:
[tex]p_f = mv+MV[/tex]
where:
m = 0.006 kg is the mass of the bullet
M = 1.4 kg is the mass of the rifle
v = 800 m/s is the velocity of the bullet
V is the recoil velocity of the rifle
The total momentum is conserved, therefore we can write:
[tex]p_i = p_f[/tex]
Which means:
[tex]0=mv+MV[/tex]
Solving for V, we can find the recoil velocity of the rifle:
[tex]V=-\frac{mv}{M}=-\frac{(0.006)(800)}{1.4}=-3.43 m/s[/tex]
where the negative sign indicates that the velocity is opposite to direction of the bullet: so the recoil speed is
a) 3.43 m/s