The volume of the gas at STP is 2.86L
Explanation:
Given:
Volume, V₁ = 4L
Pressure, P₁ = 0.817 atm
Temperature, T₁ = 39°C
T₁ = 39 + 273K
T₁ = 312 K
At STP,
Pressure, P₂ = 1 atm
Temperature, T₂ = 273 atm
Volume, V₂ = ?
According to the gas law:
[tex]\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}[/tex]
On substituting the value, we get:
[tex]\frac{0.817 X 4}{312} = \frac{1 X V_2}{273}\\\\V_2 = \frac{0.817X4X273}{312} \\\\V_2 = 2.86L[/tex]
Therefore, the volume of the gas at STP is 2.86L
