Answer:
Option E
Step-by-step explanation:
if [tex]n\neq[/tex] 0, let us plugging different value for n
if n=1
2n = 2 x 1 = 2>n
but if n=-1
2n= 2 x -1 = -2<n
So I is not always true
Now, for the same value of n, let us check the other two statements
[tex]n^{2}[/tex] = [tex]1^{2}[/tex] = 1 which is not greater than n
So II is also not true
2 - n = 2 - 1 = 1 which is not greater than n
So we can see that none of the statement is true,
So the correct answer is option E