Question

NEED ANSWER ASAP If the volume of a container of air is reduced by one half, what happens to the partial pressure of carbon dioxide within the container?
A. It is reduced by one half.
B. It is unchanged.
C. It is doubled.

Answer 1

Answer: The pressure of the container becomes doubled.

Explanation:

Boyle's law is one of the gas laws that is used to illustrate Ideal gas law.

This law states that pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

Mathematically,

$P\propto \frac{1}{V}$

The equation given by this law is:

$P_1V_1=P_2V_2$

where,

$P_1\text{ and }V_1$ are initial pressure and volume.

$P_2\text{ and }V_2$ are final pressure and volume.

When the volume of the container is reduced to half, the equation becomes:

$P_1=P_1\\V_1=V_1\\P_2=?\\V_2=\frac{V_1}{2}$

Putting values in above equation, we get:

$P_1\times V_1=P_2\times \frac{V_1}{2}\\\\P_2=\frac{P_1\times V_1\times 2}{V_1}=2P_1$

Hence, the pressure of the container becomes doubled.