Question

in dogs there is a hereditary type of deafness caused by a recessive gene. Two dogs who carry the gene for deafness but have normal hearing are mated. what are the possible genotypes and phenotypes of their offspring and the percent of chance for each?

Answer 1

Answer:

in dogs there is a hereditary type of deafness caused by a recessive gene. Two dogs who carry the gene for deafness but have normal hearing are mated. what are the possible genotypes and phenotypes of their offspring and the percent of chance for each?

Dd x Dd = DD, Dd, Dd, and dd

3:1 genotype

phenotype shows that there is 3 dominant gene for normal hearing while 1 for deafness (two homozygous where 1 is dominant and the other is recessive) and (two heterozygous with normal hearing dominant over deafness recessive)

Explanation:

Answer 2

The possible genotypes are DD - 25%, Dd - 50%, and dd - 25% while the possible phenotypes are normal hearing - 75% and deafness - 25%.

The two dogs carry the deafness gene but have normal hearing. This means that the deafness gene is recessive to normal hearing. Assuming that the deafness gene is represented by d, the normal hearing would be D.

                               Dd    x    Dd

                          DD   Dd   Dd   dd

Possible genotypes and their percents

DD - 25%

Dd - 50%

dd - 25%

Possible phenotypes and their percents

Normal hearing - 75%

Deafness - 25%

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