Respuesta :
Answer:
a) [tex]n = 9604[/tex]
b) n = 381
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].
The margin of error is:
[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
90% confidence level
So [tex]\alpha = 0.1[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.1}{2} = 0.95[/tex], so [tex]Z = 1.645[/tex].
a. Assume that nothing is known about the percentage of computers with new operating systems. n = ?
When we do not know the proportion, we use [tex]\pi = 0.5[/tex], which is when we are going to need the largest sample size.
The sample size is n when M = 0.01.
[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
[tex]0.01 = 1.96\sqrt{\frac{0.5*0.5}{n}}[/tex]
[tex]0.01\sqrt{n} = 1.96*0.5[/tex]
[tex]\sqrt{n} = \frac{1.96*0.5}{0.01}[/tex]
[tex](\sqrt{n})^{2} = (\frac{1.96*0.5}{0.01})^{2}[/tex]
[tex]n = 9604[/tex]
b. Assume that a recent survey suggests that 99% of computers use a new operating system. n = ?
Now we have that [tex]\pi = 0.99[/tex]. So
[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
[tex]0.01 = 1.96\sqrt{\frac{0.99*0.01}{n}}[/tex]
[tex]0.01\sqrt{n} = 1.96*\sqrt{0.99*0.01}[/tex]
[tex]\sqrt{n} = \frac{1.96*\sqrt{0.99*0.01}}{0.01}[/tex]
[tex](\sqrt{n})^{2} = (\frac{1.96*\sqrt{0.99*0.01}}{0.01})^{2}[/tex]
[tex]n = 380.3[/tex]
Rouding up
n = 381
Based on the information given, the number of computers that must be surveyed in order to be 90% confident assume that nothing is known about the percentage of computers will be 423.
When nothing is known about the percentage of computers with new operating systems, the number of computers will be:
= [1.645² × 0.5 × (1 - 0.5)] / 0.04²
= 423
Assume that a recent survey suggests that 99% of computers use a new operating system, the number of computers will be:
= [1.645² × 0.90 × (1 - 0.90)] / 0.04²
= 152
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