leenabusamhadaowuzlx leenabusamhadaowuzlx
  • 31-03-2020
  • Mathematics
contestada

Given sinx= −3/5 when 3π/2 < x < 2π, find tan x/2
A. -√3
B. -1/3
C. -1
D. -√3/3

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jakaylamason21 jakaylamason21
  • 31-03-2020
BBBBBBBBB!!! yes i believe it’s B
Answer Link
amna04352
amna04352 amna04352
  • 31-03-2020

Answer:

B -⅓

Step-by-step explanation:

sinx = -3/5

Adjacent² = 5² - 3² = 16

Adjacent = 4

Tan(x) = -3/4

-¾ = 2tan(½x)/[1 - tan²(½x)]

-3 + 3tan²(½x) = 8tan(½x)

3tan²(½x) - 8tan(½x) - 3 = 0

tan(½x) = 3, -⅓

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