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Answer:
17. HC₂H₃O₂ + H₂O ⇄ C₂H₃O₂⁻ + H₃O⁺ Ka
A B CB CA
18. H₂SO₄ + 2H₂O → 2H₃O⁺ + SO₄⁻²
A B CA CB
19. CO₃⁻² + H₂O ⇄ HCO₃⁻ + OH⁻ Kb
B A AC BC
20. HCO₃⁻ + NH₃ ⇄ CO₃⁻² + NH₄⁺ Ka
A B BC AC
21. NH₄⁺ + OH⁻ ⇄ NH₃ + H₂O Ka
A B BC AC
Explanation:
The acetic acid release a proton to water, to produce acetate and hydronium.
This is a weak acid.
The sulfuric acid release 2 protons to water to produce sulfate and hydronium.
This acid is considered as strong, but it is only strong in the first dissociation. The second dissociation is weak, with a Ka.
Carbonate takes a proton from water, to become bicarbonate (In this case, the carbonate behaves as a base).
Bicarbonate release a proton to ammonia, to make ammonium and carbonate anion.
Amonium cation release a proton to the hydroxide to make ammonia and water.
Answer:
See explanation
Explanation:
Step 1: Data given
Bronsted-Lowry says the following:
Acid dissociation: HX + H2O → H3O+ + X-
Base dissociation: B + H2O → OH- + HB+
HC2H3O2 + H2O →
HC2HO2 is acetic acid, it's a weak acid. (CH3COOH)
This will be following the reaction HX + H2O → H3O+ + X-
CH3COOH + H2O → CH3COO- + H3O+
H2SO4 + H2O →
H2SO4 is a strong acid
This will be following the reaction HX + H2O → H3O+ + X-
H2SO4 + H2O → HSO4- + H3O+
CO3^2- + H2O →
CO3^2_ is a conjugate base
This will be following the reaction B + H2O → OH_ + HB+
CO3^2- + H2O → HCO3- + OH-
HCO3- + NH3 →
HCO3- (known as bicarbonate) is the conjugate base of H2CO3, a weak acid, and the conjugate acid of the carbonate ion.
NH3 is a weak base
HCO3- + NH3 → CO3^2- + NH4+
NH4+ + OH- →
The hydrogen on the ammonium ion (NH4+) can go back to the hydroxide ion (OH-) to form NH3 and H2O (ammonia and water) again. In this case, because the ammonium ion is donating a proton, it is called a conjugate acid.
NH4+ + OH- → NH3 + H2O