Answer:
The length of the radius of the circle is 7 mm
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
If HK is tangent to circle O at point K
then
The radius OK is perpendicular to segment HK and triangle OKH is a right triangle
Applying the Pythagorean Theorem
[tex]OH^2=OK^2+HK^2[/tex]
we have
[tex]OH=(r+18)\ mm\\OK=r\ mm\\HK=24\ mm[/tex]
substitute
[tex](r+18)^2=r^2+24^2[/tex]
solve for r
[tex]r^2+36r+324=r^2+576[/tex]
[tex]36r=576-324\\36r=252\\r=7\ mm[/tex]
therefore
The length of the radius of the circle is 7 mm