Answer:
Distance of the object is 8.6 m
Explanation:
As we know that the speed of sound at t degree C is given as
[tex]v = 332 + 0.6 t[/tex]
here we know that the temperature is
t = 20 degree C
so we have
[tex]v = 332 + 0.6(20)[/tex]
[tex]v = 344 m/s[/tex]
now we know that bat heard the echo of sound in 0.05 s
so the to and fro distance of the object is d + d = 2d
so we have
[tex]2 d = v\times t[/tex]
[tex]2d = 344(0.05)[/tex]
[tex]d = 8.6 m[/tex]