Answer:
Step-by-step explanation:
y=x² ln(x)sin 2x
taking log of both sides
log y=log(x² in(x)sin 2x)=log x²+log.ln (x)+log (sin2 x)
=2log x+log .ln(x)+log sin 2x
diff. w.r.t.x
1/y×(dy/dx)=2/x+(1/ln(x))×(1/x)+( 2 cos 2x/sin2x)
dy/dx=y[2/x+(1/x.ln(x))+2 cot 2x]
dy/dx=x² in(x) sin (2x)[2/x+1/xin(x)+2 cot 2x]
