Question

A Sample of helium measuring 6l was kept at a pressure of 1.5atm. If pressure is doubled what would be its new volume?

Answer 1

Answer: 30.5

Explanation:

V1 = 61

P1 = 1.5

P2 = 2P1 ( 2X1.5) =3

V2 =?

Using Boyle's law; V1P1 = V2P2

$\frac{V_{1}P_{1}}{P_{2}}=\frac{61(1.5)}{3} = \frac{91.5}{3}$

= 30.5

Therefore:

The new volume = 30.5