Answer:
[tex]a_{10}[/tex] = 42
Step-by-step explanation:
The n th term I obtained in your previous question, that is
[tex]a_{n}[/tex] = 4n + 2
To find the 10 th term substitute n = 10 into the formula
[tex]a_{10}[/tex] = 4(10) + 2 = 40 + 2 = 42
Answer:
Step-by-step explanation:
this linear sequence means : An = an+b
n=1 A1 = a(1)+b=6
n=2 A2=a(2)+b=10
you have the system : a+b=6...(*)
2a+b =10...(**)
from (*) : b=6-a
from (**) : b= 10-2a
10-2a=6-a
-2a+a=6-10
-a=-4
a=4
b=6-a =6-4 = 2
An = 4n+2..... the nth term
the 10th term is :A10 = 4(10)+2=42
other solution : for the nth term
this aritmetic seq when the first term is A1 = 6
the common diference is d= 22-18=18-14=14-10=10-6=4
the nth term is : An =A1+(n-1)d =6+4(n-1) =6+4n-4 =4n+2
