Question

1a. A spring takes a force of 5.ON to extend it by 2.0cm. What is the spring
constant in N/m?
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Answer 1

Spring force is given be kx.

Where k is spring constant and x is the distance moved.

Using this relation,

$5N = k(2 \times {10}^{ - 2}m ) \\ \\ k = 250N {m}^{ - 1}$

Answer 2

Answer:

Use Hooke's law

Explanation:

1. Apply formula: F = kx
2. Sub values in: 5 = 0.02k
3. Use algebra: k = 250
4. The spring constant is 250 N/m