Respuesta :
Reactant C is the limiting reactant in this scenario.
Explanation:
The reactant in the balanced chemical reaction which gives the smaller amount or moles of product is the limiting reagent.
Balanced chemical reaction is:
A + 2B + 3C → 2D + E
number of moles
A = 0.50 mole
B = 0.60 moles
C = 0.90 moles
Taking A as the reactant
1 mole of A reacted to form 2 moles of D
0.50 moles of A will produce [tex]\frac{2}{1}[/tex] = [tex]\frac{x}{0.50}[/tex]
thus 0.50 moles of A will produce 1 mole of D
Taking B as the reactant
2 moles of B reacted to form 2 moles of D
0.60 moles of B reacted to form x moles of D
[tex]\frac{2}{2}[/tex] = [tex]\frac{x}{0.6}[/tex]
x = 2 moles of D is produced.
Taking C as the reactant:
3 moles of C reacted to form 2 moles of D
O.9 moles of C reacted to form x moles of D
[tex]\frac{2}{3}[/tex] = [tex]\frac{x}{0.9}[/tex]
= 0.60 moles of D is formed.
Thus C is the limiting reagent in the given reaction as it produces smallest mass of product.
Reactant C should be considered as the limiting reactant in this given situation.
Identification of the limiting reactant(s):
Since
A balanced chemical reaction is:
A + 2B + 3C → 2D + E
And, number of moles should be
A = 0.50 mole
B = 0.60 moles
C = 0.90 moles
Now here we considered A as the reactant
So,
1 mole of A reacted to form 2 moles of D
0.50 moles of A will produce = 1 mole of D
Now considered B as the reactant
2 moles of B reacted to form 2 moles of D
0.60 moles of B reacted to form x moles of D
x = 2 moles of D is produced.
Now considered C as the reactant:
3 moles of C reacted to form 2 moles of D
O.9 moles of C reacted to form x moles of D
= 0.60 moles of D is formed.
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