Question

This system has an equilibrium constant of 0.105 at 472°C: N2(g) + 3H2(g) ↔ 2NH3(g)


What is the reaction quotient, Q, for this system when [N2] = 2.00 M, [H2] = 2.00 M, and [NH3] = 1.00 M at 472°C?

0.0625

0.1250

0.2500

0.5000

Answer 1

Answer:

What is the reaction quotient, Q, for this system when [N2] = 2.00 M, [H2] = 2.00 M, and [NH3] = 1.00 M at 472°C?

A. 0.0625

How does Q compare to Keq?

B. Q < Keq

Explanation:

Answer 2

The value of the reaction quotient, Q is 0.0625.

What is the reaction quotient?

The reaction quotient Q is a measure of the relative amounts of products and reactants present in a reaction at a given time.

Solution :

Given,

Concentration of  $N_{2}$ = 2.00 M

Concentration of  $H_{2}$ = 2.00 M

Concentration of $NH_{3}$ = 1.00 M

Reaction quotient: It is defined as a concentration of a chemical species involved in the chemical reaction.

The balanced equilibrium reaction is,

$N_{2}+3H_{2}\ \leftrightharpoons 2NH_{3}$

The expression of reaction quotient for this reaction is,

$Q=\frac{[Product]^p}{[Reactanct]^r}$

$Q=\frac{[NH_3]^2}{[N_2]^1[H_2]^3}$

Now put all the given values in this expression, we get

Q = 0.0625.

Therefore, the value of reaction quotient, Q is 0.0625.

Learn more about reaction quotient here:

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