Need help please and thank you

Given:
Center (3.2, -2.1)
Radius = 4.3
To find:
The equation of the circle.
Solution:
The standard form of an equation of a circle:
[tex](x-h)^{2}+(y-k)^{2}=r^{2}[/tex]
where r is the radius and (h, k) is the center.
Here (h, k) = (3.2, -2.1) and r = 4.3
Substitute this in the standard form.
[tex](x-3.2)^{2}+(y-(-2.1))^{2}=(4.3)^{2}[/tex]
[tex](x-3.2)^{2}+(y+2.1)^{2}=(4.3)^{2}[/tex]
The equation of the circle is [tex](x-3.2)^{2}+(y+2.1)^{2}=(4.3)^{2}[/tex].