Question

Hey spinning with nine equal sections number one through nine the probability of spinning at three is one night what is the probability of not spinning at three

Answer 1

Answer:

8/9

Step-by-step explanation:

In this problem, the spin has nine equal sections.

This means that the probability of spinning each section is equal, and it is given by

$p(x_i) = \frac{1}{n}$

where n is the number of sections.

Here,

n = 9

So the probability of each section is

$p(x_i)=\frac{1}{9}$

In fact, here we are told that the probability of spinning a 3 is

$p(x=3)=\frac{1}{9}$

The complementary probability of an event is the probability that the event does not occur; it is given by

$p(x^C)=1-p(x)$

In this problem, $p(x)=\frac{1}{9}$ (probability of spinning a 3), therefore the probability of NOT spinning a 3 is:

$p(x\neq 3)=1-p(x=3)=1-\frac{1}{9}=\frac{8}{9}$