Answer:
P = $1664.12 pay with 9% compounded monthly
P = 1652.98 pay with 9% compounded continuously
Explanation:
given data
time period = 20 year
amount = $10000
solution
we get here compound interest for 9% compounded monthly that is express as
FV = [tex]P\times (1+\frac{r}{n})^{nt}[/tex] .................1
here P is principal amount and r is interest rate and n compound in year and FV is future value
$10000 = [tex]P\times (1+\frac{r0.09}{12})^{12\times 20}[/tex]
solve it we get
P = $1664.12 pay with 9% compounded monthly
and
for 9% compounded continuously
FV = [tex]P\times e^{rt}[/tex] ............2
$10000 = P\times e^{0.09\times 20}
solve it we get
P = 1652.98 pay with 9% compounded continuously