Question

What is the value of A when we rewrite 3.14^159x as A^x?

Answer 1

The rule we'll use is

p^(q*r) = (p^q)^r

The exponents have been rearranged a bit.

In this case, p = 3.14, q = 159 and r = x, so,

p^(q*r) = (p^q)^r

3.14^(159*x) = (3.14^159)^x

This is in the form A^x with A = 3.14^159