Answer:
Therefore the number of product is 11.42 to minimize the average cost .
Step-by-step explanation:
Given that,
[tex]C(x)=4x^3-16x^2+12,000x[/tex]
where C(x) is cost of manufacturing of x items.
Differentiating with respect to x
[tex]C'(x)=12x^2-32x+12,000[/tex]
Again differentiating with respect to x
[tex]C''(x)=24x-32[/tex]
To find the minimum cost, we set C'(x)=0
[tex]\therefore 12x^2-32x-1200=0[/tex]
[tex]\Rightarrow 4(3x^2-8x-300)=0[/tex]
[tex]\Rightarrow 3x^2-8x-300=0[/tex] [ since 4≠0]
Applying quadratic formula [tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex], here a= 3, b= -8, c=-300
[tex]\therefore x=\frac {-(-8)\pm\sqrt{(-8)^2-4.3.(-300)}}{2.3}[/tex]
=11.42, -8.76
The number of item is negative, it can't make sense.
∴x=11.42
Now
[tex]C''|_{x=11.42}=24(11.42)-32=242.08>0[/tex]
Therefore when x= 11.42, the cost of manufacturing will minimum.
Therefore the number of product is 11.42 to minimize the average cost .