Respuesta :
Answer:
Check Explanation
Step-by-step explanation:
a) Let the fixed insurance fee be A and the rate charged per hour be b
The equation for the cost, C, of flying lessons in terms of length, h, of the course in hours is given by
C = A + bh
b) The two points (h, C) given in the question are (8, 645) and (20, 1425)
c) To find the equation of the line passing through these two points,
equation of a straight line iS given by
y = mx + c (where m = slope of the line and c = intercept)
denoting hours (h) as x and Cost (C) as y
645 = 8m + c
1425 = 20m + c
Solving this simultaneous equation,
m = 65 dollars/hour and c = 125 dollars
The equation of the straight line is
y = 65x + 125
Written in the variables of the question,
C = 65h + 125
This shows that the fixed insurance fee, called A in part (a) = $125
And the rate charged per hour called b in part (a) = $65/hour
Hope this Helps!!!
Answer:
Y = $125 + $65x
Step-by-step explanation:
in order to write an euation for the cost and flying lesson, high and low method will be used
cost hours
High $1425 20
Low $645 8
780 12
varaible cost per hr(b) = $780/12 = $65
equation of straight line
Y = a + bx
a = fixed cost , b = variable cost , x = hours of the course , Y = total cost
to calculate a , using high
therefore Y = $1425 , x = 20
1425 = a + 65(20)
1425 - 1300 = a
a = $125
the equation is therefore,
Y = $125 + $65x
