Answer:
Radius of the circular is equal to 1.286 m
Explanation:
We have given magnetic field B = 0.5 T
Magnetic flux [tex]\Phi =2.6weber[/tex]
It is given that magnetic field and plane are perpendicular to each other
So angle between magnetic field and area vector is 0
Magnetic field is equal to [tex]\Phi =BAcos\Theta[/tex]
So [tex]2.6=0.5\times A\times cos0^{\circ}[/tex]
[tex]A=5.2m^2[/tex]
Area of the circular loop is equal to [tex]A=\pi r^2[/tex]
[tex]5.2=3.14\times r^2[/tex]
r = 1.286 m
So radius of the circular loop is equal to 1.286 m