Answer:
the transmission axis of polarizing sheet makes an angle of [tex]\Theta =26.74^{\circ}[/tex] with the horizontal
Explanation:
We have given that intensity of light incident on the sheet [tex]I_0=0.970W/m^2[/tex]
Average intensity of light emerging from a polarizing sheet [tex]I=0.775W/m^2[/tex]
We have to find the angle between transmission axis with the horizontal
Intensity of light polarizing from sheet is equal to [tex]I=I_0cos^2\Theta[/tex]
So [tex]0.775=0.970cos^2\Theta[/tex]
[tex]cos^2\Theta =0.798[/tex]
[tex]cos\Theta =0.893[/tex]
[tex]\Theta =26.74^{\circ}[/tex]
So the transmission axis of polarizing sheet makes an angle of [tex]\Theta =26.74^{\circ}[/tex] with the horizontal