Answer:26.9L
Explanation: this is Charles' law which states that the volume of a gas is directly proportional to the absolute temperature at contant pressure. The expression is V1/T1 = V2/T2
Making V2 the subject of the formula we have
V2 = V1 xT2/T1
= 22.4 x 328/273
= 26.9L
Taking into account the Charles's law, the same amount of gas at the same pressure and 55 ∘C would occupy a volume of 26.91 L.
Charles's Law consists of the relationship that exists between the volume and the temperature of a certain quantity of ideal gas, which is maintained at a constant pressure.
This law states that the volume is directly proportional to the temperature of the gas: if the temperature increases, the volume of the gas increases, while if the temperature of the gas decreases, the volume decreases.
Mathematically, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the quotient that exists between the volume and the temperature will always have the same value:
[tex]\frac{V}{T}=k[/tex]
Studying an initial state 1 and a final state 2, it is satisfied:
[tex]\frac{V1}{T1}=\frac{V2}{T2}[/tex]
In this case, you know:
Replacing:
[tex]\frac{22.4 L}{273 K}=\frac{V2}{328 K}[/tex]
Solving:
[tex]V2=328 Kx\frac{22.4 L}{273 K}[/tex]
V2= 26.91 L
Finally, the same amount of gas at the same pressure and 55 ∘C would occupy a volume of 26.91 L.
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