Answer:
1. the real power lost is 7.5 MW
2. the real power lost by adding capacitors is 4.8 MW
Explanation:
1.
[tex]|I|=\frac{300x10^{6} }{\sqrt{3}*250*\sqrt{3}*0.8*10^{3} } =500A[/tex]
the real power lost is
[tex]P=3|I|^{2} R=3*500^{2} *10=7500000W=7.5MW[/tex]
2.
[tex]|I|=\frac{P}{\sqrt{3}V } =\frac{300x10^{6} }{\sqrt{3}*\sqrt{3}*250*10^{3} } =400A[/tex]
the real power lost is
[tex]P=3*400^{2} *10=4800000W=4.8MW[/tex]