Question

The intensive care unit lab process has an average turnaround time of 26.2 minutes and a standard deviation of 1.35 minutes. The nominal value for this service is 25 minutes 5 minutes. Is the lab process capable of four sigma-level performance

Answer 1

Answer: yes

Explanation:

Upper specification = 30 minutes

Lower specification = 20 minutes

Average service = 26.26minutes

Sigma= 1.35 minutes

Answer 2

The lab process is capable of four sigma level performance.

The average turnaround = 26.2

Standard deviation = 1.35 minutes

Nominal value for service = 25 minutes

Upper specification= 30 minutes

Lower specification = 20 minutes

$Cpk = Minimum[\frac{X-lower specification}{3Sigma} ,\frac{Upperspecification-X}{3sigma} ]$

$Cpk =Minimun [\frac{26.2-20}{3*1.35} ,\frac{30-26.2}{3*1.35} ]\\\\= Min[1.53, 0.94]$

The minimum is 0.94.

$Cp = \frac{Upper-lower}{6Sigma} \\\\Cp = \frac{30-20}{6*1.35} \\\\= 1.23$

The lab process is capable of four sigma level performance.

Read more on https://brainly.com/question/4050666?referrer=searchResults