Explanation:
Given that,
An oceanic depth-sounding vessel surveys the ocean bottom with ultrasonic waves that travel at 1530 m/s in seawater, v = 1530 m/s
The time delay of the echo to the ocean floor and back is 6 s, t = 6 s
The distance covered by the wave to reach its echo is 2d. The formula of speed is given by :
[tex]v=\dfrac{2d}{t}\\\\d=\dfrac{vt}{2}\\\\d=\dfrac{1530\ m/s\times 6\ s}{2}\\\\d=4590\ m[/tex]
So, the depth of the water directly below the vessel is 4590 m. Hence, proved.