Answer: The molar concentration of Z in the solution is 2.15 M
Explanation:
We are given:
23% (w/w) Z in solution
This means that 23 grams of Z is present in 100 grams of solution
To calculate the volume of solution, we use the equation:
[tex]\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}[/tex]
Density of solution = 1.3 g/mL
Mass of solution = 100.0 g
Putting values in above equation, we get:
[tex]1.3g/mL=\frac{100g}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{100g}{1.3g/mL}=76.92mL[/tex]
To calculate the molarity of solution, we use the equation:
[tex]\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}[/tex]
Given mass of Z = 23 g
Molar mass of Z = 139 g/mol
Volume of solution = 76.92 mL
Putting values in above equation, we get:
[tex]\text{Molarity of solution}=\frac{23\times 1000}{139\times 76.92}\\\\\text{Molarity of solution}=2.15M[/tex]
Hence, the molar concentration of Z in the solution is 2.15 M