If the charge q₁ is tripled then the force between the charged becomes 3 times the original charge.
Explanation:
Given:
Distance between the two charges = r
The force between two charges is given by:
[tex]F_1 = k\frac{q_1q_2}{r^2}[/tex]
If q₁ is tripled, then the force F becomes:
[tex]F_2 = k\frac{(3q_1)Xq_2}{r^2}[/tex]
[tex]\frac{F_2}{F_1} = \frac{3q_1q_2}{r^2} X \frac{r^2}{q_1q_2}\\\\F_2 = 3F_1[/tex]
Therefore, if the charge q₁ is tripled then the force between the charged becomes 3 times the original charge.
