Question

A low-pressure weather system comes into the city of Denver. The atmospheric pressure is 683 mmHg. If 78.0 % of dry air is nitrogen, what is the partial pressure of nitrogen in this low-pressure system?

Answer 1

Answer: 532.74 mmHg

Explanation:

The atmospheric pressure is stated to be 683 mmHg with nitrogen accounting for 78.0% of dry air.

To calculate this therefore you take 78% of the total atmospheric pressure to account for that of Nitrogen.

= 78/100 * 683

= 532.74 mmHg

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Answer 2

The partial pressure of nitrogen in this low-pressure system should be  532.74 mmHg.

Calculation of the partial pressure:

Since The atmospheric pressure is 683 mmHg. And, 78.0 % of dry air is nitrogen

So here the partial pressure should be

= 78/100 * 683

= 532.74 mmHg

hence, The partial pressure of nitrogen in this low-pressure system should be 532.74 mmHg.

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