Answer:
The value of the test statistic is -0.979
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 11.1 hours
Sample mean, [tex]\bar{x}[/tex] = 10.7 hours
Sample size, n = 24
Alpha, α = 0.05
Sample standard deviation, s = 2.0 hours
First, we design the null and the alternate hypothesis
[tex]H_{0}: \mu = 11.1\text{ hours}\\H_A: \mu \neq 11.1\text{ hours}[/tex]
We use two-tailed t test to perform this hypothesis.
Formula:
[tex]t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }[/tex]
Putting all the values, we have
[tex]t_{stat} = \displaystyle\frac{10.7 - 11.1}{\frac{2}{\sqrt{24}} } = -0.979[/tex]
Thus, the value of the test statistic is -0.979