Question

A loop of area 0.820 m2 is in a uniform magnetic field B = 0.646 T. The magnetic flux through the loop is 0.200 Wb. What is the angle between the the normal to the plane of the loop and the field? (Give the smallest positive angle.)

Answer 1

Answer:

67.81°

Explanation:

Magnetic flux, Φ, is given as:

Φ = B*A*cosθ

Where B = magnetic field

A = area of loop

θ = angle

Therefore:

cosθ = Φ/(B*A)

cosθ = 0.2/(0.646 * 0.82)

cosθ = 0.3776

θ = 67.81°