Answer:
The standard deviation of the voltage is 0.5825V.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
[tex]\mu = 0[/tex]
False signal:
higher than 1.5V.
What is the standard deviation of voltage such that the probability of a false signal is 0.005.
This means that when X = 1.5, Z has a pvalue of 1-0.005 = 0.995. So when X = 1.5, Z = 2.575.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]2.575 = \frac{1.5 - 0}{\sigma}[/tex]
[tex]2.575\sigma = 1.5[/tex]
[tex]\sigma = \frac{1.5}{2.575}[/tex]
[tex]\sigma = 0.5825[/tex]
The standard deviation of the voltage is 0.5825V.