Answer:
[tex]m_{H_2}=0.0574gH_2[/tex]
Explanation:
Hello,
In this case, the information about the pressure, volume and temperature are enough to compute the mass of hydrogen assuming its ideal behavior:
[tex]n_{H_2}=\frac{PV}{RT}=\frac{739mmHg*\frac{1atm}{760mmHg}*0.722 L}{0.082 \frac{atm*L}{mol*K}*298.15K} =0.0287molH_2[/tex]
The mass is:
[tex]m_{H_2}=0.0287molH_2*\frac{2gH_2}{1molH_2} \\m_{H_2}=0.0574gH_2[/tex]
Best regards.