Question

You did an experiment in which you found that 59.8 J was required to raise the temperature of 25.0 g of ethylene glycol ( a compound used as antifreeze in automobile engines) by 1.00 Kelvin. Calculate the specific heat capacity of ethylene glycol from these data

Answer 1

Answer:

specific heat capacity of ethylene glycol = 2.392 J. K⁻¹. g⁻¹

Explanation:

Heat obtained(q) = 59.8 J

Change in temperature (ΔT) = 1 .00 K

From this data we can calculate the specific heat capacit of ethylene glycol

The specific heat capacity (Cs) = $\frac{q}{mXT}$

                             Mass of ethylene glycol(m) = 25 g

                        So specific heat capacity $=\frac{59.8}{25X1} = 2.392 JK^{-1}g^{-1}$

From this data we can calculate the specific heat capacit of ethylene glycol

So, specific heat capacity of ethylene glycol = 2.392 J. K⁻¹. g⁻¹