Question

An electron is placed in a magnetic field that is directed along a z axis. The energy difference between parallel and antiparallel alignments of the z component of the electron's spin magnetic moment with is 4.80 ✕ 10−25 J. What is the magnitude of ?

Answer 1

Answer:

$2.59\times 10^{-2} T$

Explanation:

We are given that

Energy difference,$\Delta E=4.8\times 10^{-25} J$

We have to find the magnitude of  B.

Bohr magneton=$\mu_B=9.274\times 10^{-24} J/T$

We know that magnetic field ,B=$\frac{\Delta E}{2(\mu_B)}$

By using the formula

$B=\frac{4.8\times 10^{-25}}{2\times 9.274\times 10^{-24}}$

$B=0.0259=2.59\times 10^{-2} T$

Hence, the magnitude of B=$2.59\times 10^{-2} T$