Question

determine the specific heat of a material if a 35g sample absorbed 96 J as it was heated from 293 K to 313 K?

Answer 1

Answer:

0.137 J/g*C

Explanation:

Cp= k-273.15

T1= 293-273.15 = 19.85 C

T2= 313 -273.15 = 39.85 C

DeltaT= T2-T1 = 20 C

96/35x20 = 0.137 J/g*C

the "C" is supposed to be Celsius

don't ask me to further explain what you already see here