Question

Unpolarized light of intensity 25.8 W/cm2 is incident on two polarizing filters. The axis of the first filter is at an angle of 25.6 ∘ counterclockwise from the vertical (viewed in the direction the light is traveling) and the axis of the second filter is at 57.0 ∘ counterclockwise from the vertical. What is the intensity of the light after it has passed through the second polarizer?

Answer 1

Answer:

$I_{0} = 9.359 W/cm^2$

Explanation:

$I_{0} = 25.8 W/cm^2 (given)\\ \theta _{1} = 25.6^{0}\\ \theta _{2} = 57^{0}\\\\I_{1} = I_{0}/2\\I_{1} = 0.5 I_{0}\\I_{2} = I_{0}cos^2(57^{0}-25.6^{0})$

on solving these equation

$I_{2} = 0.5I_{0}cos^2(31.4^{0})$$.$

$I_{0} = 0.5I_{0}(0.85)^2$

$I_{0} = 0.5*25.8*0.7225$

$I_{0} = 9.359 W/cm^2$