Answer:
19.9 miles
Step-by-step explanation:
In this problem we have:
[tex]d_1=1 mi[/tex] is the distance travelled during the 1st day
[tex]d_2=1.3 mi[/tex] is the distance travelled during the 2nd day
[tex]d_3=1.9 mi[/tex] is the distance travelled during the 3rd day
[tex]d_4=3.1 mi[/tex] is the distance travelled during the 4th day
We notice that the difference between the distance travelled on the (n+1)-th day and the distance travelled on the n-th day doubles every day. In fact:
[tex]d_2-d_1=0.3\\d_3-d_2=2\cdot 0.3 = 0.6\\d_4-d_3=2\cdot 0.6 = 1.2[/tex]
Which can be rewritten using the general formula:
[tex]d_{n+1}-d_n=2(d_n-d_{n-1})[/tex]
This means that
[tex]d_{n+1}=d_n+2(d_n-d_{n-1})[/tex]
By applying this formula recursively, we can find the 7th term, which is the distance travelled on the 7th day:
[tex]d_1=1\\d_2=1.3\\d_3=1.9\\d_4=3.1\\d_5=3.1+2\cdot 1.2=5.5\\d_6=5.5+2\cdot 2.4=10.3\\d_7=10.3+2\cdot 4.8=19.9 mi[/tex]
So, the distance travelled on the 7th day is 19.9 miles.