Question

When sodium metal is added to water, the following reaction occurs: 2Na(s) + 2H2O(l) → 2NaOH(aq) + H2(g) What is the theoretical number of moles of hydrogen gas produced when 0.068 mol of sodium metal reacts?

Answer 1

Answer:

$n_{H_2}^{Theoretical}=0.034molH_2$

Explanation:

Hello,

In this case, based on the given rewritten reaction:

$2Na(s) + 2H_2O(l) \rightarrow 2NaOH(aq) + H_2(g)$

The stoichiometry leads to the following theoretical moles of oxygen:

$n_{H_2}^{Theoretical}=0.068molNa*\frac{1molH_2}{2molNa}=0.034molH_2\\n_{H_2}^{Theoretical}=0.034molH_2$

As sodium and hydrogen as a 2 to 1 molar relationship.

Best regards.