Answer:
0.24
Explanation:
We are given that
Rate constant for A=[tex]k=0.0180/s[/tex]
Rate constant for B,k'=0.0750/s
We have to find the value of equilibrium constant for the reaction
[tex]A\rightleftharpoons B[/tex]
Equilibrium constant, for k=[tex]\frac{k}{k'}[/tex]
Using the formula
[tex]k=\frac{0.0180}{0.0750}=0.24[/tex]
Hence, the value of the equilibrium constant for the reaction
[tex]A\rightleftharpoons B[/tex] at this temperature=0.24